9/ 08/2014 Find the value of e ^{log e2 9}. Note: The exponent is log _e² 9.




Scroll down for the solution.

9/08/2014 Solution. Let e ^{log e2 9} = p

→ log _e p = log _e2 9

→ log p / ln e = log 9 / ln e²

→ log p / ln e = log 9 / 2·ln e

Cross-multiplying:
→ 2 log p = log 9

→ log p = ½ log 9

→ log p = log √9

→ p = 3

Therefore, e ^{log e2 9} = 3.