9/1/2014
Suppose
there’s a 53% likelihood that a child born is Male. If a family
has 6 children, what is the probability that at least 1 shall be a
boy?
Scroll
down for the solution.
9/1/2014 Solution. P(B) = 0.53
P(at
least 1 boy amongst 6 children)
= 1 – P(no boy at all
amongst the 6 children)
= 1 – P(B', B', B', B', B')
= 1
– P(B')6,
assuming independence
= 1 – 0.476
= 98.92%