**8/23/2014****
****If
f(x) = 3x**^{2
}**+
4x + 5, what must the value of ***k***
****be
so that the graph of f(x – ***k***)
is symmetric about the y-axis?a) -4 b) -4/3 c) -2/3
d) 2/3 e) 4/3**

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down for the solution.**

**8/23/2014**
Solution.
**D**.
Upon completing the square, f(x) = 3(x + 2/3)^{2}
+ 11/3, with the Axis of
Symmetry being x = -2/3 so that f(x – 2/3) would shift it 2/3
units to the right and make it symmetric about the y-axis, so *k*
= -2/3.