9/04/2014 Consider regular pentagon ABCDE such that DEFG is a square. Find the measures of ∠EAF, ∠AFD and ∠DAF.
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9/04/2014
Solution.
Sketch
a figure to satisfy the given conditions.
Since ABCDE is a
regular pentagon, the interior angle ∠AED
= 108°, and ∆ADE
is an isosceles triangle, ∠ADE
= 36°. Also, ∠AEF
= 162° since ∠DEF
= 90° and ∠AED
= 108° [subtracting from 360°]. As ∆AEF
is an isosceles triangle, ∠EAF
= 9° = ∠AFE.
Therefore, ∠DAF
= 36°
+
9°
=
45° and ∠AFD
= 45°
+
9°
=
54°.
∠EAF
= 9°, ∠AFD
= 54° and ∠DAF
= 45°.