**9/1/2014****
**Suppose
there’s a 53% likelihood that a child born is Male. If a family
has 6 children, what is the probability that at least 1 shall be a
boy?**Scroll
down for the solution.**

**9/1/2014
**Solution.
**P(B)
=****
****0.53****
**

P(at
least 1 boy amongst 6 children)

= 1 – P(no boy at all
amongst the 6 children)

= 1 – P(B', B', B', B', B')

= 1
– P(B')^{6},
assuming independence

**=
1 – 0.47**^{6
}

**=
98.92%**